Count possibilities by branches
If each first choice has the same number of continuations, multiply the counts. Make sure the outcomes really are distinguishable pairs.
| Shirt | Possible hats | Count |
|---|---|---|
| Red | A, B, C | 3 |
| Blue | A, B, C | 3 |
| Total | 2 × 3 | 6 |
One worked example
- Coin: heads or tailsThe first step has 2 possibilities.
- Die: 1 to 6 for each coin sideEach branch has 6 continuations.
- 2 × 6 = 12 pairsFor example, (heads, 1) differs from (tails, 1).
Watch out: If some pairs are forbidden, a simple product may not apply. Counting outcomes alone does not show that they are equally likely.
Goal, prerequisites and card origin
What you will learn: Count all pairs from two successive choices.
What you need first: Multiplication of small numbers.
An original PEAZIT working card. Independent expert review and effectiveness testing have not yet taken place. · v1
Show connections
If each first choice has the same number of continuations, multiply the counts. Make sure the outcomes really are distinguishable pairs.