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PEAZIT Aha card

Quadratic equations: roots from the discriminant

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For ax² + bx + c = 0, identify a, b, c including their signs. D = b² − 4ac determines the number of real roots.

The equation x² − 5x + 6 = 0 has two ± branches.
ExpressionMeaning
a = 1; b = −5; c = 6The right side is already zero.
D = (−5)² − 4 · 1 · 6 = 1D is positive: two distinct real roots.
x = (5 ± √1)/2; x = 2; x = 3Use x = (−b ± √D)/(2a).

One worked example

  1. a = 1; b = −5; c = 6The right side is already zero.
  2. D = (−5)² − 4 · 1 · 6 = 1D is positive: two distinct real roots.
  3. x = (5 ± √1)/2; x = 2; x = 3Use x = (−b ± √D)/(2a).

Watch out: D = 0 gives one repeated root; D < 0 gives no real roots. If a = 0, the equation is not quadratic.

Goal, prerequisites and card origin

What you will learn: Use the quadratic formula when a is nonzero.

What you need first: Powers, square roots and substitution with signs.

An original PEAZIT working card. Independent expert review and effectiveness testing have not yet taken place. · v1

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For ax² + bx + c = 0, identify a, b, c including their signs. D = b² − 4ac determines the number of real roots.

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