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PEAZIT Aha card

Parabolas: read the vertex from the square

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A square is at least 0, attained at x = h. For a > 0 the lowest point is (h, k); for a < 0 it is the highest point.

For y = (x − 2)² + 1, neighbouring values are symmetric.
ExpressionMeaning
x = 2 → y = 1The bracket is zero: the vertex is (2, 1).
x = 1; x = 3 → y = 2Equal distance from 2 gives equal y.
x = 0; x = 4 → y = 5The axis of symmetry is x = 2.

One worked example

  1. x = 2 → y = 1The bracket is zero: the vertex is (2, 1).
  2. x = 1; x = 3 → y = 2Equal distance from 2 gives equal y.
  3. x = 0; x = 4 → y = 5The axis of symmetry is x = 2.

Watch out: For a < 0, the parabola has a maximum, not a minimum over all real x. In (x + 2)², h = −2.

Goal, prerequisites and card origin

What you will learn: Find the vertex and minimum from y = a(x − h)² + k.

What you need first: Squares and point coordinates.

An original PEAZIT working card. Independent expert review and effectiveness testing have not yet taken place. · v1

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A square is at least 0, attained at x = h. For a > 0 the lowest point is (h, k); for a < 0 it is the highest point.

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